Not to terminate ev_loop
sandeep at b-one.net
Sun Jan 8 08:51:51 CET 2012
No, I did not copy that. Ok, I will simply my problem statement to as
minimal as I can.
If I take the example code as below:
As of now the below program will print "stdin-ready" only once as soon as
user enters input and then exits
My intention is to make it into a program where it will all the time be
running waiting for user input to STDIN (not just 1 shot), and each time
user enters an input the program must print "stdin-ready" without exiting.
In my experimentation with very minimal knowledge and time, I have
intentionally commented out the functions ev_io_stop and ev_unloop in both
stdin_cb and timeout_cb, but as expected what is happening is,
"stdin-ready" gets called as soon as user enters something and immediately
stdin-ready is called in an infinite loop.
Could you please help me how to modify this in such a way that, call
"stdin_cb" everytime there is input (but not simply in infinite loop), if
there is no input just keep waiting without exiting.
stdin_cb (EV_P_ struct ev_io *w, int revents)
puts ("stdin ready");
// for one-shot events, one must manually stop the watcher
// with its corresponding stop function.
//ev_io_stop (EV_A_ w);
// this causes all nested ev_loop's to stop iterating
//ev_unloop (EV_A_ EVUNLOOP_ALL);
timeout_cb (EV_P_ struct ev_timer *w, int revents)
// this causes the innermost ev_loop to stop iterating
//ev_unloop (EV_A_ EVUNLOOP_ONE);
struct ev_loop *loop = ev_default_loop (0);
ev_io_init (&stdin_watcher, stdin_cb, /*STDIN_FILENO*/ 0, EV_READ);
ev_io_start (loop, &stdin_watcher);
ev_timer_init (&timeout_watcher, timeout_cb, 5.5, 0.);
ev_timer_start (loop, &timeout_watcher);
ev_loop (loop, 0);
// unloop was called, so exit
From: John Newton [mailto:jnewton at gmail.com]
Sent: Sunday, January 08, 2012 11:30 AM
Subject: Re: Not to terminate ev_loop
Did you copy the example code that calls the following?
ev_break (EV_A_ EVBREAK_ONE);
ev_break() tells the ev_loop() to exit.
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